| MF_Row_divrV
| MD_Row_divrV |
ME_Row_divrV |
| MCF_Row_divrV |
MCD_Row_divrV |
MCE_Row_divrV |
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| Funktion | Element-weise umgekehrte Division: Vektor durch eine Zeile einer Matrix teilen und die Zeile mit dem Ergebnis überschreiben |
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| Syntax C/C++ | #include <MFstd.h>
void MF_Row_divrV( fMatrix MA, ui ht, ui len, ui iRow, fVector X ); |
| C++ MatObj | #include <OptiVec.h>
void matrix<T>::Row_divrV( const ui iRow, const vector<T>& X); |
| Pascal/Delphi | uses MFstd;
procedure MF_Row_divrV( MA:fMatrix; ht, len, iRow:UIntSize; X:fVector ); |
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| CUDA-Funktion C/C++ | #include <cudaMFstd.h>
int cudaMF_Row_divrV( fMatrix d_MA, ui ht, ui len, ui iRow, fVector d_X );
void MFcu_Row_divrV( fMatrix h_MA, ui ht, ui len, ui iRow, fVector h_X ); |
| CUDA-Funktion Pascal/Delphi | uses MFstd;
function cudaMF_Row_divrV( d_MA:fMatrix; ht, len, iRow:UIntSize; d_X:fVector ): IntBool;
procedure MFcu_Row_divrV( h_MA:fMatrix; ht, len, iRow:UIntSize; h_X:fVector );
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| Beschreibung | MAiRow,i = Xi / MAiRow,i, i=0,...,len-1 |
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